SQL SERVER 2005 com PHP

[MGProjects]

bem estava tentando fazer uma conexão com o sql 2005 com o php do apache..

estou com esse erro quando abro a pagina

Notice: Use of undefined constant sql_host - assumed 'sql_host' in C:\wamp\www\_inc\config.php on line 9

Notice: Use of undefined constant sql_user - assumed 'sql_user' in C:\wamp\www\_inc\config.php on line 9

Notice: Use of undefined constant sql_pass - assumed 'sql_pass' in C:\wamp\www\_inc\config.php on line 9

Notice: Use of undefined constant sql_db - assumed 'sql_db' in C:\wamp\www\_inc\config.php on line 13

codigo da conexão

<?php

$cfg['sql_host'] = "ZULU631\SQLEXPRESS";

$cfg['sql_user'] = "sa";

$cfg['sql_pass'] = "A0168t21";

$cfg['sql_db'] = "SRO_VT_ACCOUNT";

$sqlLink = mssql_connect($cfg[sql_host],$cfg[sql_user],$cfg[sql_pass]);

if(!$sqlLink) die("MSSQL server is not accessable, why should we try to select database ?");

else

{

mssql_select_db($cfg[sql_db],$sqlLink);

}

?>

codigo do index.

<?php

/* Simple registration page for silkroad server, by Chernobyl

* Settings are at _inc/config.php

* If you get an mssql connection error, while defining totally correct data

* Just use older ntwdblib.dll for your webserver

*/

require_once('_inc/security.class.php');

require_once('_inc/config.php');

if(!isset($_POST['submit']))

{

echo "<table border=1'>

<form method='post'>

<td>Username</td><td><input type='text' name='username' maxlength='16'></td><tr/>

<td>Password[1]</td><td><input type='password' name='pw1' maxlength='32'></td><tr/>

<td>Password[2]</td><td><input type='password' name='pw2' maxlength='32'></td><tr/>

<td></td><td><input type='submit' name='submit' value='Register'></td>

</form>

</table>";

}

else

{

if(strlen($_POST['username]) < 3) $msg[] = "Username too short";

if(strlen($_POST['username']) > 16)$msg[] = "Username too long";

if(strlen($_POST['pw1']) < 6) $msg[] = "Password [1] too short";

if(strlen($_POST['pw1']) > 32)$msg[] = "Password [1] too long";

if(strlen($_POST['pw2']) < 6) $msg[] = "Password [2] too short";

if(strlen($_POST['pw2']) > 32) $msg[] = "Password [2] too long";

if($_POST['pw1'] != $_POST['pw2']) $msg[] = "Passwords are not the same";

$sec = new security();

if($sec->is_secure($_POST['username']) == false) $msg[] = "Username contains forbidden symbols";

if($sec->is_secure($_POST['pw1']) == false) $msg[] = "Password [1] contains forbidden symbols";

if($sec->is_secure($_POST['pw2']) == false) $msg[] = "Password [2] contains forbidden symbols";

if(count($msg) > 0)

{

for($i = 0; $i < count($msg); $i++)

{

echo $msg[$i]."<br/>";

}

return;

}

else

{

//checking damn mssql stuff

$accountExists = mssql_num_rows(mssql_query("select StrUserID from TB_User where StrUserID=$_POST[username]'"));

if($accountExists > 0) echo "Account with such username already exists<br/>";

else

{

$pwd = md5($_POST['pw1]);

mssql_query("insert into TB_User(StrUserID,password,sec_primary,sec_content) values('$_POST[username]','$pwd','3','3')");

echo "Account successfully created<br/>";

}

}

}

?>

ai quando eu do ok para add na tabela ele aparece

Password [1] too short

Password [2] too short

mais não add nada na dbo

Edited September 24, 2011 by MGProjects

[Willian Gustavo Veiga]

Notice: Use of undefined constant XXX - assumed 'XXX' in C:\wamp\www\_inc\config.php on line X

Este erro indica que você esqueceu de colocar aspas ou apóstrofo na chave do array, dessa maneira o PHP assumiu que você estava utilizando uma constante.

Um abraço.