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(Resolvido) campos de bits


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Sim!

Independentemente da arquitetura, os sistemas atuais, tem um inteiro CHAR de 8 bits.

Se mapearmos um a um em estrutura, e aplicamos cast é possível manipula-los individualmente.

Veja como:

/** @authr Mauro Britivaldo
* License all free on edition and published */
#include <stdio.h>
                                          //MANUAL TRACE
typedef struct byte byte;                 //Definido a nossa estrutura
struct byte {                             //Mapeamos Bit a Bit com campos da mesma
   unsigned char b0: 1;
   unsigned char b1: 1;
   unsigned char b2: 1;
   unsigned char b3: 1;
   unsigned char b4: 1;
   unsigned char b5: 1;
   unsigned char b6: 1;
   unsigned char b7: 1;
   };

int main (void)   {
//
   char c_caracter;                       //Declaramos uma variável inteira
   byte *bt;                              //Declaramos um ponteiro da estrutura


      bt = (byte*) &c_caracter;
      bt->b4 = 1;                         //Manipulamos em baixo nível; bit a bit := |16|
                                          //Observe o resultado
      
     //
      printf ("Before: Show byte: %d\n", c_caracter);

      bt->b4 = 0;
      printf ("After:  Show byte: %d\n", c_caracter);

   return 0;
   } 
Edited by britivaldo
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